412.FizzBuzz（javascript）

给你一个整数 n ，找出从 1 到 n 每个整数的 Fizz Buzz 表示并使用字符串数组 answer（下标从 1 Start）返回结果，其中：

• answer[i] == “FizzBuzz” 如果 i 同时是 3 和 5 的倍数。
• answer[i] == “Fizz” 如果 i 是 3 的倍数。
• answer[i] == “Buzz” 如果 i 是 5 的倍数。
• answer[i] == i （以字符串形式），如果不满足上述条件。

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == “FizzBuzz” if i is divisible by 3 and 5.、
• answer[i] == “Fizz” if i is divisible by 3.
• answer[i] == “Buzz” if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

示例 1：

输入：n = 3
输出：["1","2","Fizz"]

示例 2：

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例 3：

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

var fizzBuzz = function (n) {
    let newList = new Array(n).fill(0)
    for (let i = 0; i < newList.length; i++) {
        newList[i] = i + 1;
        if (newList[i] % 15 == 0) {
            newList[i] = "FizzBuzz";
        } else if (newList[i] % 3 == 0) {
            newList[i] = "Fizz";
        } else if (newList[i] % 5 == 0) {
            newList[i] = "Buzz";
        }else{
            newList[i] = newList[i].toString();
        }
    }
    return newList
};

leetcode： https://leetcode-cn.com/problems/fizz-buzz/